How much oxygen is consumed when combusting a mixture of 20 liters of ethylene and 10 liters of methane?

1) First, calculate:
C2H4 + 3O2 = 2CO2 + 2H2O
CH4 + 2O2 = CO2 + 2H2O
22.4 – 67.2
20 – x
x = 60

2) Let’s make the proportion:
22.4 – 44.8
10 – x
x = 20
60 + 20 = 80 l



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