How much oxygen is needed to burn 1 liter of C4H10 butane?

The combustion reaction of butane is described by the following chemical reaction equation:

C4H10 + 6.5 O2 = 4CO2 + 5H2O;

For the combustion of 1 mole of butane, 6.5 moles of oxygen are required. This produces four moles of carbon dioxide and five moles of water.

One mole of ideal gas under normal conditions takes a fixed volume of 22.4 liters.

Therefore, for the combustion of 1 liter of butane, 1 x 6.5 = 6.5 liters of oxygen is required.