How much oxygen is needed to burn 10 mol of propane?

The propane oxidation reaction is described by the following chemical reaction equation.

C3H8 + 5O2 = 3CO2 + 4H2O;

According to the coefficients of this equation, 5 oxygen molecules are required to oxidize 1 propane molecule. This synthesizes 3 molecules of carbon dioxide.

There are 10 moles of propane.

The amount of oxygen will be.

N O2 = 10 x 5 = 50 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V O2 = 50 x 22.4 = 1120 liters;