How much oxygen is needed to burn 100 liters of methane?

univerkov | September 25, 2021 | education

Let us write the methane combustion equation:

CH4 + 2O2 = CO2 + 2H2O.

Let’s calculate the amount of methane moles reacted.

n (CH4) = V / Vm = 100 L / 22.4 mol / L = 4.46 mol.

Oxygen in relation to methane will be twice as much.

n (O2) = 2 * 4.46 = 8.93 mol.

The volume of oxygen is equal to:

V (О2) = n * Vm = 8.93 mol * 22.4 mol / l = 200 liters.

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