How much oxygen is needed to burn 160 g of calcium?

The combustion reaction of calcium is described by the following chemical reaction equation:
Ca + 1/2 O2 = CaO;
One mole of calcium reacts with half a mole of oxygen. This forms one mole of calcium oxide.
Let’s find the amount of the substance in 160 grams of calcium. To do this, divide the mass of calcium by its molar mass.
M Ca = 40 grams / mol;
N Ca = 100/40 = 2.5 mol;
To burn 2.5 moles of calcium, 2.5 / 2 = 1.25 moles of oxygen are needed.
One mole of ideal gas under normal conditions takes a fixed volume of 22.4 liters.
The required volume of oxygen will be:
V O2 = 1.25 x 22.4 = 28 liters.