How much oxygen is needed to burn 20 liters of propane?

The propane oxidation reaction is described by the following chemical reaction equation.
C3H8 + 5O2 = 3CO2 + 4H2O;
According to the coefficients of this equation, 5 oxygen molecules are required to oxidize 1 propane molecule. This synthesizes 3 molecules of carbon dioxide.
Let’s calculate the amount of propane available.
To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.
N C3H8 = 20 / 22.4 = 0.893 mol;
The amount of oxygen will be.
N O2 = 0.893 x 5 = 4.465 mol;
Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.
Its volume will be: V O2 = 4.465 x 22.4 = 100 liters;