How much oxygen is needed to burn 20 mol of methane?
| February 19, 2021 | education
1. Combustion of methane in oxygen is described by the reaction equation:
CH4 + O2 = CO2 + 2H2O;
2.the amounts of methane and oxygen according to the reaction equation are related as 1: 1:
n (O2) = n (CH4) = 20 mol;
3.Calculate the volume of oxygen required for the reaction:
V (O2) = n (O2) * Vm = 20 * 22.4 = 448 liters.
Answer: 448 l.
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