How much oxygen is needed to burn 22.4 liters of hydrogen?

The interaction of hydrogen with oxygen is described by the following chemical reaction equation:

H2 + 1/2 O2 = H2O;

Let’s calculate the chemical amount of hydrogen. To do this, we divide its volume by the volume of 1 mole of the substance (which is 22.4 liters).

N H2 = 22.4 / 22.4 = 1 mol;

With this amount of hydrogen, 1/2 = 0.5 mol of oxygen will react.

Let’s define its volume.

To do this, multiply the amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).

V O2 = 0.5 x 22.4 = 11.2 liters;