How much oxygen is needed to burn 24 g of carbon?

The reaction of carbon with oxygen takes place according to the following chemical reaction equation:

C + O2 = CO2;

For oxidation of 1 mole of carbon, 1 mole of oxygen is required.

Let’s find the amount of carbon.

M C = 12 grams / mol;

N C = 24/12 = 2 mol;

To burn this amount of carbon, 2 moles of oxygen are required.

Let’s find its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The oxygen volume will be equal to:

V O2 = 2 x 22.4 = 44.8 liters;