How much oxygen is needed to burn 4.6 grams of sodium (Na)?

1. Let us write down the reaction equation (it must be remembered that peroxide is formed when alkali metals are burned, with the exception of lithium):

2Na + O2 = Na2O2.

2. Find the amount of sodium:

n (Na) = m (Na) / M (Na) = 4.6 g / 23 g / mol = 0.2 mol.

3. Using the equation, we find the amount of oxygen and its volume (Vm – molar volume, constant equal to 22.4 mol / l):

n (O2) = 0.5n (Na) = 0.1 mol.

V (O2) = n (O2) * Vm = 0.1 mol * 22.4 mol / L = 2.24 L.

Answer: V (O2) = 2.24 liters.



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