How much oxygen is needed to burn 4 liters of ethane?
| June 24, 2021 | education
Decision:
1. Let’s compose the equation of the reaction of interaction of ethane with oxygen:
2C2H6 + 7O2 = 4CO2 + 6H2O;
2. Find the amount of substance in ethane, dividing the volume by the molar volume:
4 / 22.4 = 0.1785 mol
3. Before oxygen in the equation there is a coefficient 3.5 times higher than before ethane. Therefore, the amount of substance in oxygen is 0.1785 * 3.5 = 0.625 mol.
4. Let’s find the volume of oxygen:
0.625 * 22.4 = 14 liters
Answer: the required volume of oxygen is 14 liters.
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