How much oxygen is needed to burn 5.6 liters of acetylene?

The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:

2C2H2 + 5O2 = 4CO2 + 2H2O;

2 moles of acetylene are reacted with 5 moles of oxygen.

Let’s calculate the available chemical amount of the acetylene substance.

To do this, we divide the volume of gas by the volume of 1 mole of ideal gas. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N C2H2 = 5.6 / 22.4 = 0.28 mol;

To burn such an amount of matter, you need to take 0.28 x 5/2 = 0.7 mol of oxygen.

The oxygen volume will be:

V O2 = 0.7 x 22.4 = 15.68 liters;