How much oxygen is needed to burn 5 liters of methane?

univerkov | December 7, 2020 | education

To find the volume you need:
CH4 + 2O2 = CO2 + 2H2O (reaction equation)
1) n (CH4) = V / Vm = 5 L / 22.4 L / mol = 0.223 mol
2) n (O2) = 2 * 0.223 = 0.446 mol
and find the volume V (O2) = n * Vm = 0.446 * 22.4 l / mol = 9.99 l

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