How much oxygen is needed to interact with 2.7 g of aluminum?

univerkov | May 24, 2021 | education

4Al + 3O2 = 2Al2O3;

according to the equation, the amounts of aluminum and oxygen are related as 4: 3, we calculate the chemical amount of aluminum and express the amount of oxygen:

n (Al) = 2.7: 27 = 0.1 mol;

n (O2) = n (Al) * 3: 4 = 0.1 * 3: 4 = 0.075 mol.

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