How much oxygen is needed to interact with 700 grams of iron containing 20% impurities?

univerkov | December 10, 2020 | education

mass of pure iron = 700 * 0.8 = 560 g
n (Fe) = 560: 56 = 10 mol
3Fe + 2O2 = Fe3O4
n (O2) = n (Fe): 3 * 2 = 10: 3 * 2 = 6.66 mol
v (O2) = 6.66 * 22.4 = 149.3
answer 149.3 liters

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.