How much oxygen is needed to obtain 80 liters of carbon monoxide (IV) from coal?

The carbon oxidation reaction is described by the following chemical reaction equation:

C + O2 = CO2;

Carbon reacts with oxygen in equal molar amounts.

The same amount of carbon dioxide will be synthesized.

Let’s define the chemical amount of a substance in 80 liters of carbon monoxide.

To do this, we divide its volume by the volume of 1 mole of gaseous substance.

N CO 2 = 80 / 22.4 = 3.571 mol;

The same amount of oxygen will be required.

Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V O2 = 3.571 x 22.4 = 80 liters;