How much oxygen is needed to oxidize 42 liters of sulfur (IV) oxide to sulfur (VI) oxide?
| May 14, 2021 | education
1. We make a chemical equation, not forgetting to put down the coefficients:
2SO2 + O2 = 2SO3.
2. Let’s find the amount of substance SO2:
n (SO2) = V / Vm = 42 / 22.4 = 1.875 mol.
3. Let’s find the amount of substance О2:
n (О2) = n (SO2) / 2 = 0.9375 mol.
4. Let’s find the volume of oxygen:
V (O2) = n * Vm = 0.9375 * 22.4 = 21l.
Answer: V (O2) = 21l.
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