How much oxygen is required for a complete structure of 10 liters. acetylene?

The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:

2C2H2 + 5O2 = 4CO2 + 2H2O;

2 moles of acetylene are reacted with 5 moles of oxygen.

Let’s calculate the available chemical amount of acetylene.

To do this, we divide the volume of gas by the volume of 1 mole of ideal gas, equal to 22.4 liters.

N C2H2 = 10 / 22.4 = 0.446 mol;

To burn such an amount of matter, you need to take 0.446 x 5/2 = 1.115 mol of oxygen.

The oxygen volume will be:

V O2 = 1.115 x 22.4 = 24.976 liters;