How much oxygen is required for the combustion of 2 mol (2.24) acetylene?

In order to solve this problem, we first compose the equation of reactions and get the following:
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
We know the following formula, by which we find the volume of acetylene:
V = n × Vm
Where V is the volume
n is the amount of substance
Vm is the molar volume.
V = 10 × 22.4 = 224 l
Next, we make up the proportion
224 l C2H2 has Chl O2
2 × 22.4 this is 5 × 22.4
Further, from the proportion, we find the value x
X = 5 × 22.4 × 224/2 × 22.4 = 560 (L)
V (O2) = 560 HP
Answer: the volume of oxygen is 560 liters.