How much oxygen is required for the combustion of 2 mol of methane CH4?
| September 27, 2021 | education
The methane oxidation reaction is described by the following chemical reaction equation.
CH4 + 2O2 = CO2 + 2H2O;
According to the coefficients of this equation, the oxidation of 1 methane molecule requires 2 oxygen molecules. This synthesizes 1 molecule of carbon dioxide.
The molar volume of the gas is standard and fills a volume of 22.4 liters under normal conditions.
2 moles of methane fill a volume of 2 x 22.4 = 44.8 liters.
Since the molar volume of gas is standard, twice the amount of oxygen will require twice the volume of oxygen.
The required volume of oxygen will be 44.8 x 2 = 89.6 liters.
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