How much oxygen is required for the complete oxidation of 112 g of iron?

Iron oxidation proceeds according to the reaction:
4Fe + 3O2 = 2Fe2O3.
Iron reacts in amounts:
112 g: 56 g / mol = 2 mol.
Oxygen is needed in the amount of 3/4 of the amount of Fe. By volume at n.u. it will be:
2 mol * 0.75 * 22.4 l / mol = 33.6 l.

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