How much oxygen is required for the complete oxidation of 2 mol of ethanol?

The ethanol oxidation reaction is described by the following chemical reaction equation.

C2H5OH + 3O2 = 2CO2 + 3H2O;

According to the coefficients of this equation, for the oxidation of 1 molecule of alcohol, 3 molecules of oxygen are required. In this case, 2 molecules of carbon dioxide are synthesized.

N C2H5OH = 2 mol;

The amount of oxygen will be.

N O2 = 2 x 3 = 6 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V O2 = 6 x 22.4 = 134.4 liters;