How much oxygen is required for the oxidation of 2 mol of sulfur (if it exhibits a valence of 4)

univerkov | May 20, 2021 | education

Given:
n (S) = 2 mol

To find:
V (O2) -?

Decision:
1) Write the reaction equation:
S + O2 => SO2;
2) Determine the amount of substance O2:
n (O2) = n (S) = 2 mol;
3) Calculate the volume of O2:
V (O2) = n (O2) * Vm = 2 * 22.4 = 44.8 liters.

Answer: The O2 volume is 44.8 liters.

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