How much oxygen is required for the oxidation of calcium weighing 8 g?

The reaction of calcium with oxygen takes place according to the following chemical reaction equation:

Ca + ½ O2 = CaO;

For the oxidation of 1 mol of calcium, 0.5 mol of oxygen is required.

Let’s find the amount of calcium.

M Ca = 40 grams / mol;

N Ca = 8/40 = 0.2 mol;

To burn this amount of calcium, 0.2 / 2 = 0.1 mol of oxygen is required. The same amount of calcium oxide will be obtained.

Let’s find its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The oxygen volume will be equal to:

V O2 = 0.1 x 22.4 = 2.24 liters;