How much oxygen is required to burn 10 liters of ethene?

Let’s implement the solution:
C2H4 + 3O2 = 2CO2 + 2H2O;
Combustion of ethylene in oxygen is accompanied by the release of carbon dioxide and water.
Determine the number of moles of ethylene if the volume occupied by it is known V (C2H4) = 10 liters
According to Avogadro’s law, 1 mol (C2H4) – takes a volume of 22.4 liters
Thus, X = 1 * 10 / 22.4 = 0.45 mol.
Let’s make a proportion based on the data on the reaction equation:
0.45 mol (C2H4) – X mol (O2);
hence X mol (O2) = 0.45 * 3/1 = 1.35 mol
Let’s calculate: V (O2) = 1.35 * 22.4 = 30.24L
Answer: For the combustion of ethylene, 30.24 liters of oxygen are required.