How much oxygen is required to burn 112 grams of calcium?

univerkov | December 23, 2020 | education

2Ca + O2 = 2CaO
Given:
m (Ca) = 112 g
Vm = 22.4 g / mol
Decision:
v (Ca) = m / M
M (Ca) = 40 g / mol
v (Ca) = 112 g / 40 g / mol = 0.36 mol (rounded off)
v (Ca) = 2 (O2) = 0.36 * 2 = 0.72 mol
V (O2) = v * Vm = 0.72 * 22.4 = 16.13 l
Answer: 16.13 l

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