How much oxygen is required to burn 2.4 g of magnesium in it?

The combustion reaction of magnesium is described by the following chemical reaction equation.

Mg + ½ O2 = MgO;

According to the chemical reaction equation, for the combustion of 1 mole of magnesium, 0.5 mole of oxygen is required.

Let’s determine the amount of a substance contained in 2.4 grams of magnesium. To do this, we divide the mass of magnesium by its molar mass.

M Mg = 24 grams / mol;

N Mg = 2.4 / 24 = 0.1 mol;

For combustion of 0.1 mol of magnesium, 0.05 mol of oxygen is required.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of oxygen.

V O2 = 0.05 x 22.4 = 1.12 liters;