How much oxygen is required to burn 24 grams of calcium?
| April 7, 2021 | education
write down the reaction equation and arrange the coefficients: 2Ca + O2 = 2CaO
Let’s find the amount of substance Ca. To do this, we divide the mass by the molar mass
n (Ca) = m (Ca) / M (Ca) = 24/40 = 0.6 mol
from the reaction equation it is seen that oxygen is required half as much
n (O2) = 0.3 mol
All gases under normal conditions occupy the same volume – Vm = 22.4 l / mol
V (O2) = Vm * n (O2) = 22.4 * 0.3 = 6.72 L
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