How much oxygen is required to burn 250 liters of CH4 methane?

The methane oxidation reaction is described by the following chemical reaction equation.

CH4 + 2O2 = CO2 + 2H2O;

According to the coefficients of this equation, the oxidation of 1 methane molecule requires 2 oxygen molecules. This synthesizes 1 molecule of carbon dioxide.

The molar volume of the gas is standard and fills a volume of 22.4 liters under normal conditions.

Since the molar volume of gas is standard, twice the amount of oxygen will require twice the volume of oxygen.

The required volume of oxygen is 250 x 2 = 500 liters.



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