How much oxygen is required to burn 320 g of sulfur?

The reaction of sulfur with oxygen is described by the equation:

S + O2 = SO2;

Substances interact in the same molar amounts.

Let’s determine the chemical amount of sulfur.

M S = 32 grams / mol; N S = 320/32 = 10 mol;

Find the volume of 10 mol of oxygen. For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters).

V O2 = 22.4 x 10 = 224 liters;