How much oxygen is required to burn 36g of carbon?

Given:
m (C) = 36 g

Find:
V (O2) -?

1) O2 + C => CO2;
2) n (C) = m / M = 36/12 = 3 mol;
3) n (O2) = n (C) = 3 mol;
4) V (O2) = n * Vm = 3 * 22.4 = 67.2 liters.

Answer: The O2 volume is 67.2 liters.



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