How much oxygen is required to burn 40g of octene?

1. Let’s write down the solution according to the condition of the problem:
m = 40 g. X l. -?
С8Н16 + 12О2 = 8СО2 + 8Н2О + Q – the combustion reaction is accompanied by the release of heat, carbon dioxide and water;
2. We make calculations:
M (C8H16) = 112 g / mol;
Y (C8H16) = m / M = 40/112 = 0.375 mol.
3. We make up the proportion:
0.375 mol (C8H16) – X mol (O2);
-1 mol – 12 mol from here, X mol (O2) = 0.375 * 12/1 = 4.284 mol.
4. Find the volume of O2:
V (O2) = 4.284 * 22.4 = 95.96 liters.
Answer: you need oxygen in a volume of 95.96 liters.