How much oxygen is required to burn 5.4 g of aluminum?
| June 20, 2021 | education
The reaction of aluminum with oxygen is described by the following chemical reaction equation:
4Al + 3O2 = 2Al2O3;
That is, for 4 moles of aluminum, 3 moles of oxygen are needed.
The molar mass of aluminum is 27 grams / mol
The number of moles of a substance in 5.4 grams of aluminum is 5.4 / 27 = 0.211 mol;
The required amount of oxygen will be 0.211 x 3/4 = 0.15825 mol;
Under normal conditions, 1 mole of ideal gas takes up a volume of 22.4 liters.
This amount of gas occupies a volume under normal conditions equal to 0.15825 x 22.4 = 3.5448 liters.
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