How much oxygen is required to burn 5 moles of butyne?

Let’s write down the solution step by step:
1. Let’s compose the reaction equation:
2С4Н6 + 11О2 = 8СО2 + 6Н2О – the combustion reaction of butyne is accompanied by the release of carbon dioxide;
2. Let’s make a proportion based on the data of the reaction equation:
5 mol (C4H6) – X mol (O2);
-2 mol              -11 mol from here, X mol (O2) = 11 * 5/2 = 27.5 mol;
3. Let’s calculate the volume of oxygen, taking into account Avogadro’s law:
V (O2) = 27.5 * 22.4 = 616 liters.
Answer: to burn butyne, you need 616 liters of oxygen.