How much oxygen is required to burn 500 m3 of methane? Reaction scheme: CH4 + O2 → CO2 + H2O

Under normal conditions, 1 mole of any gas occupies a volume of 22.4 liters. This is the molar volume – Vm. In order to calculate the volume of gas, use the formula Vgas = Vm * n (gas), where V is the volume, n is the amount of substance in moles.
From this it is clear that the volume of gas is affected only by its amount
Let’s arrange the coefficients:
CH4 + 2O2 = CO2 + 2H2O
From the reaction equation, we can conclude that the combustion of 1 mol of methane will take 2 mol of oxygen, that is, based on the previous reasoning, 500m3 of methane – 1000m3 of oxygen.