How much oxygen is required to burn 500 m3 of methane?

The methane combustion reaction is described by the following chemical reaction equation:

CH4 + 2O2 = CO2 + 2H2O;

It takes two moles of oxygen to burn one mole of methane.

The molar volume of an ideal gas is constant and occupies a fixed volume of 22.4 liters, regardless of the composition.

Since oxygen requires a double molar volume, its volume will be twice the volume of methane and will be 500 x 2 = 1,000 m3.



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