How much oxygen is required to burn 60g of magnesium containing 15% impurities?

univerkov | December 10, 2020 | education

mass of pure magnesium = 60 * 0.85 = 51 g
n (Mg) = 51: 24 = 2.125
2Mg + O2 = 2MgO
2n (o2) = n (Mg)
n (O2) = 1.0625
1 mol of gas at low takes 22.4 liters
hence the volume of oxygen = 22.4 * 1.025 =
answer 23.8 liters

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.