How much oxygen is required to interact with 16g of hydrogen?

2H2 + O2 = 2H2O
According to the periodic table, we determine the molar mass of hydrogen, equal to 2 g / mol.
Let’s find the amount of hydrogen reacted: n (H2) = m / M = 16 g / 2 g / mol = 8 mol.
According to the equation, 2 mol of H2 reacts with 1 mol of O2. Let’s make the proportion: 8 mol / 2 mol = n (O2) / 1 mol. Hence n (O2) = 4 mol. To find the volume, we use the formula: V = n * Vm, where Vm = 22.4 l / mol is the molar volume, a constant for all gases under normal conditions. V (O2) = 4 mol * 22.4 L / mol = 89.6 L.



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