How much oxygen is required to interact with iron weighing 100 g, if the reaction results in iron oxide (III).

Given:
m (Fe) = 100 g

To find:
V (O2) -?

1) 4Fe + 3O2 => 2Fe2O3;
2) n (Fe) = m / M = 100/56 = 1.79 mol;
3) n (O2) = n (Fe) * 3/4 = 1.79 * 3/4 = 1.34 mol;
4) V (O2) = n * Vm = 1.34 * 22.4 = 30 liters.

Answer: The O2 volume is 30 liters.



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