How much oxygen is required to obtain 80 g CuO.

Let’s implement the solution:
1. Let’s write the equation according to the problem statement:
X l. -? m = 80 g;
2Cu + O2 = 2CuO – compound reaction, copper oxide was obtained;
2. Calculations:
M (CuO) = 79.5 g / mol;
Y (CuO) = m / M = 80 / 79.5 = 1 mol.
3. Proportion:
1 mol (СuO) – x mol (О2);
-2 mol – 1 mol from here, X mol (O2) = 1 * 1/2 = 0.5 mol.
4. Find the volume of the original substance:
V (O2) = 0.5 * 22.4 = 11.2 liters.
Answer: to carry out the reaction, oxygen with a volume of 11.2 liters is required.