How much oxygen is required to oxidize 28 g of pyrite containing 76 percent iron sulfide?

The reaction of pyrite with oxygen is described by the following chemical equation:

4FeS2 + 11O2 = 2Fe2O3 + 8SO2;

Let’s determine the chemical amount of pyrite. To do this, divide its weight by the weight of 1 mole of the substance.

M FeS2 = 56 + 32 x 2 = 120 grams / mol;

N FeS2 = 28/120 = 0.2333 mol;

With this amount of sulfur, 0.2333 x 11/4 = 0.642 mol of oxygen will react.

Let’s calculate its volume.

To do this, multiply the amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).

V O2 = 0.642 x 22.4 = 14.37 liters;