How much oxygen is required to oxidize 4 g of hydrogen?

The reaction of hydrogen with oxygen occurs in accordance with the following chemical reaction equation:

H2 + ½ O2 = H2O;

For the oxidation of 1 mole of hydrogen, 0.5 mole of oxygen is required.

Let’s find the amount of hydrogen.

M H2 = 2 grams / mol;

N H2 = 4/2 = 2 mol;

To burn this amount of hydrogen requires 2/2 = 1 mole of oxygen. The same amount of hydrogen oxide will be obtained.

Let’s find its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The oxygen volume will be equal to:

V O2 = 1 x 22.4 = 22.4 liters;