How much oxygen is required to oxidize 46 liters of sulfur (IV) oxide to sulfur (VI) oxide?

univerkov | September 9, 2021 | education

Data: VSO2 – volume of sulfur (IV) oxide = 46 liters.

Const: Vm – molar volume (at normal conditions Vm = 22.4 l / mol).

1) Amount of sulfur (IV) oxide taken: νSO2 = VSO2 / Vm = 46 / 22.4 ≈ 2.054 mol.

2) The reaction level: 2SO3 (sulfuric anhydride (VI)) = 2SO2 (sulfur dioxide (IV)) + O2 (oxygen).

3) Amount of oxygen substance: νO2 / νSO2 = 1/2 and νO2 = νSO2 / 2 = 2.054 / 2 = 1.027 mol.

4) Oxygen volume: VO2 = νO2 * Vm = 1.027 * 22.4 ≈ 23 liters.

Answer: 2) To oxidize the taken sulfur (IV) oxide, 23 liters of oxygen are required.

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