How much oxygen (mol) is required to burn 8 moles of aluminum?
| April 26, 2021 | education
The combustion reaction of aluminum is described by the following chemical reaction equation:
4Al + 3O2 = 2Al2O3;
The reaction with 4 moles of aluminum requires 3 moles of oxygen. This produces two moles of aluminum oxide.
The required amount of oxygen will be:
N O2 = 8 x 3/4 = 6 mol;
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