How much oxygen will be consumed for the complete combustion of 2.5 g of toluene containing

How much oxygen will be consumed for the complete combustion of 2.5 g of toluene containing 4% non-combustible impurities?

The interaction of toluene with oxygen is described by the following chemical equation:

C6H5CH3 + 9O2 = 7CO2 + 4H2O;

Let’s calculate the chemical amount of toluene. To do this, divide its weight by the weight of 1 mole of the substance.

M C6H5CH3 = 12 x 6 + 5 + 12 + 3 = 92 grams / mol;

N C6H5CH3 = 2.5 x 0.96 / 92 = 0.026 mol;

With this amount of toluene, 0.026 x 9 = 0.234 mol of oxygen will react.

Let’s define its volume.

To do this, multiply the amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).

V O2 = 0.234 x 22.4 = 5.2416 liters;