How much oxygen will be released during the decomposition of 150 g of sodium peroxide?

We compose the equation for the decomposition of sodium peroxide:
2Na2O = O2 + 2Na2O – sodium oxide, oxygen are released;

We make calculations using the formulas:
M (Na2O2) = 77.8 g / mol;

M (O2) = 32 g / mol.

Determine the amount of the original substance:
Y (Na2O2) = m / M = 150 / 77.8 = 1.9 mol.

Proportion:
1.9 mol (Na2O2) – X mol (O2);

-2 mol -1 mol hence, X mol (O2) = 1.9 * 1/2 = 0.95 mol.

We find the volume of O2:
V (O2) = 0.95 * 22.4 = 21.28 L

Answer: oxygen received with a volume of 21.28 liters