How much oxygen will react with 8 liters of carbon monoxide containing 10% impurities?

The reaction of carbon monoxide with oxygen is described by the following chemical reaction equation:

CO + 1/2 O2 = CO2;

Let’s calculate the chemical amount of carbon monoxide. To do this, we divide its volume by the volume of 1 mole of the substance (which is 22.4 liters).

N CO = 8 / 22.4 = 0.357 mol;

With this amount of hydrogen, 0.357 / 2 = 0.1785 mol of oxygen will react.

Let’s define its volume.

To do this, multiply the amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).

V O2 = 0.1785 x 22.4 = 4 liters;