How much potassium chloride is required to prepare 300 ml of a solution of this salt with a concentration of 0.15 m?

Determine the required amount of a substance for preparing a solution.

To do this, multiply the volume of the solution by its molar concentration.

In order to prepare such a solution, it is necessary to weigh and dissolve 0.3 x 0.15 = 0.045 mol of salt in water.

Let’s find the required mass of salt.

To do this, we multiply the molar mass of the salt by the chemical amount of the substance.

M KCl = 39 + 35.5 = 74.5 grams / mol;

m KCl = 0.045 x 74.5 = 3.353 grams;