How much pressure is exerted on the floor by a weight of 750 N and an area of 40 cm2

How much pressure is exerted on the floor by a weight of 750 N and an area of 40 cm2 How much pressure is exerted by a column of water 60 cm high?

1)

F = 750 N;

S = 40 cm² = 40 * 0.0001 m² = 0.004 m²;

R – ?

Let us calculate the pressure exerted by the load using the formula p = F / S, where F is the force of gravity (weight), S is the area of the load.

p = 750 N / 0.004 m2 = 187500 Pa = 187.5 kPa.

2)

g = 9.8 N / kg;

ρ = 1000 kg / m³;

h = 60 cm = 60 * 0.01 m = 0.6 m;

R – ?

Let us calculate the pressure exerted by the water column by the formula р = gρh, where g is the acceleration of gravity, ρ is the density of water, and h is the height.

p = 9.8 N / kg * 1000 kg / m³ * 0.6 m = 5880 Pa.

Answer: 1) 187.5 kPa; 2) 5880 Pa.