How much propene will be consumed in the reaction with hydrogen if 7.15 mol of propane is formed?

The solution is in the following order:
1. Let’s write down the reaction equation:
С3Н6 + Н2 = С3Н8 – the propene hydrogenation reaction takes place with the participation of Pt, Ni catalysts, while the saturated hydrocarbon propane is formed;
2. Let’s make a proportion based on the data on the reaction equation:
X mol (C3H6) – 7.15 mol (C3H8);
-1 mol -1 mol. Hence, X mol (C3H6) = 7.15 mol;
3. Let’s calculate the volume of propene, taking into account Avogadro’s law:
V (C3H6) = 7.15 * 22.4 = 160.16 liters.
Answer: The reaction requires a volume of propene of 160.16 liters.